As a follow-up to yesterday’s triangle problem, here’s another one in the same equivalence class that I found at http://thinkzone.wlonk.com/MathFun/Triangle.htm (via the comments at Math With Bad Drawings). The author of this webpage tantalizingly calls this the World’s Hardest Easy Geometry Problem: solve for $x$ in the figure below.
This figure is similar to the figure in yesterday’s post, except the values of $m\angle BAE$ and $m\angle DAE$ have changed.