In the previous post, I showed a quick way of obtaining a full decimal representation using a calculator that only displays ten digits at a time. To review: here’s what a TI-83 Plus returns as the (approximate) value of :
Using this result and the Euler totient function, we concluded that the repeating block had length . So we multiply twice by
(since
) to deduce the decimal representation, concluding that
Though this is essentially multi-digit long division, most students are still a little suspicious of this result on first exposure. So here’s a second way of confirming that we did indeed get the right answer. The calculators show that
and
Therefore,
and
so that
Using the rule for dividing by , we conclude that
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