Confirming Einstein’s Theory of General Relativity With Calculus, Part 7c: Predicting Precession III

In this series, I’m discussing how ideas from calculus and precalculus (with a touch of differential equations) can predict the precession in Mercury’s orbit and thus confirm Einstein’s theory of general relativity. The origins of this series came from a class project that I assigned to my Differential Equations students maybe 20 years ago.

We have shown that the motion of a planet around the Sun, expressed in polar coordinates (r,theta) with the Sun at the origin, under general relativity is

u(\theta) \approx  \displaystyle \frac{1}{\alpha} \left[ 1 + \epsilon \cos \left( \theta - \frac{\delta \theta}{\alpha} \right) \right],

where u = \displaystyle \frac{1}{r}, \displaystyle \frac{1}{\alpha} = \frac{GMm^2}{\ell^2}, \epsilon = \displaystyle \frac{\alpha - P}{P}, \delta = \displaystyle \frac{3GM}{c^2}, G is the gravitational constant of the universe, m is the mass of the planet, M is the mass of the Sun, P is the planet’s perihelion, \ell is the constant angular momentum of the planet, and c is the speed of light.

We notice that the orbit of a planet under general relativity looks very, very similar to the orbit under Newtonian physics:

u(\theta) \approx  \displaystyle \frac{1}{\alpha} \left[ 1 + \epsilon \cos \theta \right],

so that

r(\theta) = \displaystyle \frac{\alpha}{1 + \epsilon \cos \theta}.

As we’ve seen, this describes an elliptical orbit, normally expressed in rectangular coordinates as

\displaystyle \frac{(x-h)^2}{a^2} + \frac{y^2}{b^2} = 1,

with semimajor axis along the x-axis. In particular, for an elliptical orbit, the planet’s closest approach to the Sun occurs at \theta = 0:

r(0) = \displaystyle \frac{\alpha}{1 + \epsilon \cos 0} = \frac{\alpha}{1 + \epsilon},

and the planet’s further distance from the Sun occurs at \theta = \pi:

r(\pi) = \displaystyle \frac{\alpha}{1 + \epsilon \cos \pi} = \frac{\alpha}{1 - \epsilon}.

Therefore, the length 2a of the major axis of the ellipse is the sum of these two distances:

2a =  \displaystyle \frac{\alpha}{1 + \epsilon} +  \frac{\alpha}{1 - \epsilon}

2a = \displaystyle \frac{\alpha(1-\epsilon) + \alpha(1+\epsilon)}{(1 + \epsilon)(1 - \epsilon)}

2a= \displaystyle \frac{2\alpha}{1  - \epsilon^2}

a =  \displaystyle \frac{\alpha}{1  - \epsilon^2}.

Said another way, \alpha = a(1-\epsilon^2). This is a far more convenient formula for computing \alpha than \alpha = \displaystyle \frac{\ell^2}{GMm^2}, as the values of a (the semi-major axis) and \epsilon (the eccentricity of the orbit) are more accessible than the angular momentum \ell of the planet’s orbit.

In the next post, we finally compute the precession of the orbit.

One thought on “Confirming Einstein’s Theory of General Relativity With Calculus, Part 7c: Predicting Precession III

Leave a comment

This site uses Akismet to reduce spam. Learn how your comment data is processed.