# Calculators and complex numbers (Part 19)

In this series of posts, I explore properties of complex numbers that explain some surprising answers to exponential and logarithmic problems using a calculator (see video at the bottom of this post). These posts form the basis for a sequence of lectures given to my future secondary teachers.

To begin, we recall that the trigonometric form of a complex number $z = a+bi$ is $z = r(\cos \theta + i \sin \theta) = r e^{i \theta}$

where $r = |z| = \sqrt{a^2 + b^2}$ and $\tan \theta = b/a$, with $\theta$ in the appropriate quadrant. As noted before, this is analogous to converting from rectangular coordinates to polar coordinates.

Over the past few posts, we developed the following theorem for computing $e^z$ in the case that $z$ is a complex number.

Theorem. If $z = x + i y$, where $x$ and $y$ are real numbers, then $e^z = e^x (\cos y + i \sin y)$

Example. Find all complex numbers $z$ so that $e^z = 5$.

Solution. If $z = x + iy$, then $e^x (\cos y + i \sin y) = 5 (\cos 0 + i \sin 0)$

Matching parts, we see that $e^x = 5$ and that the angle $y$ must be coterminal with $0$ radians. In other words, $x = \ln 5 \qquad$ and $\qquad y = 2\pi n$ for any integer $n$.

Therefore, there are infinitely many answers: $z = \ln 5 + 2 \pi n i$.

Notice that there’s nothing particularly special about the number $5$. This could have been any nonzero number, including complex numbers, and there still would have been an infinite number of solutions. (This is completely analogous to solving a trigonometric equation like $\sin \theta = 1$, which similarly has an infinite number of solutions.) For example, the complex solutions of the equation $e^z = -2 - 2i$

are $z = \ln 2\sqrt{2} - \displaystyle \frac{3\pi}{4} + 2 \pi n i$.

These observations lead to the following theorems, which I’ll state without proof.

Theorem. The range of the function $f(z) = e^z$ is $\mathbb{C} \setminus \{ 0 \}$.

Theorem. $e^z = e^w \Longleftrightarrow z = w + 2\pi n i$.

Naturally, these conclusions are different than the normal case when $z$ is assumed to be a real number. For completeness, here’s the movie that I use to engage my students when I begin this sequence of lectures.

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