Month: October 2016
Geometry and Halloween Costumes
From a friend’s Facebook post (shared with her permission):
For every time a geometry student asks, “When am I ever going to use this in real life?” Well, if your child ever asks you to make her a Harley Quinn costume, and there is no pattern, so you have to draft your own, you will need to find the sides of a square using the measurement of the diagonal…
[I]f you need to have a square patchwork of different colored fabrics which line up on diagonal points for a specific measurement so that you have four colored diagonal squares from the shoulder to just below the waist, you would need to find the measurement of the four equal sides of each square. Then you would add seam allowances so you could cut the squares out of the different colored fabrics and sew them together in exact lines to line up just right so you could make a top that looks like the top the character wears. And since this character is only a cartoon character who has been made into a little doll, not many people out there in the world have yet attempted an actual costume to be worn by a real live girl. Of course, a person could just take a pencil and a ruler and draw squares, but without using math, that person could not put together a patchwork of colored fabric squares with this result.
The finished product:
My Mathematical Magic Show: Part 9
This mathematical trick was not part of my Pi Day magic show but probably should have been. I first read about this trick in one of Martin Gardner‘s books when I was a teenager, and it’s amazing how impressive this appears when performed. I particularly enjoy stumping my students with this trick, inviting them to figure out how on earth I pull it off.
Here’s a video of the trick, courtesy of Numberphile:
Summarizing, there’s a way of quickly determining given the value of
if
is a positive integer less than 100:
- The ones digit of
will be the ones digit of
.
- The tens digit of
can be obtained by listening to how big
is. This requires a bit of memorization (and I agree with the above video that the hardest ones to quickly determine in a magic show are the ones less than
and the ones that are slightly larger than a billion):
- 10: At least 10,000.
- 20: At least 3 million.
- 30: At least 24 million.
- 40: At least 100 million.
- 50: At least 300 million.
- 60: At least 750 million.
- 70: At least 1.6 billion.
- 80: At least 3.2 billion.
- 90: At least 5.9 billion.
Random couscous snaps into beautiful patterns
I enjoyed watching this.
A request to the athletic department
Even though I’ve had nothing but good professional relationships with the athletic department at my own university, I still think this is really funny.
Source: http://imgur.com/vJWkqhe
English words in hexadecimal
Here’s a standard joke involving representing numbers in different bases.
Q: If only DEAD people understand hexadecimal, then how many people understand hexadecimal?
A: 57,005.
The joke, of course, is that can be considered a number written in base 16, using the usual convention
,
,
,
,
, and
. In other words,
can be converted to decimal as follows:
.
After I heard this joke, I wondered just how many English words can be formed using only the letters A, B, C, D, E, and F so that I could make a subtle joke on a test. To increase the length of my list, I also allowed words that included the letters O (close enough to a 0), I (close enough to 1), and/or S (close enough to 5). However, I eliminated words that start with O (since a numeral normally doesn’t start with 0) and/or end in S (the plural version of these words are easily formed).
So I wrote a small program to search the dictionary that I have on my computer. The unabridged list follows, with words beginning with a capital letter (such as names or places) listed at the bottom. I emphasize that this list is unabridged, as there are several words on this list that I wouldn’t place on a test for obvious reasons: I would never ask my class to convert the base-10 numeral 721,077 into hexadecimal just so they can obtain the answer of .
a
abaci
abase
abased
abbé
abed
abide
abided
abode
aboded
abscessed
abscissa
abscissae
acacia
accede
acceded
accessed
ace
aced
acid
acidic
acidified
ad
add
added
ado
adobe
aid
aide
aided
aside
assessed
b
baa
baaed
babe
babied
bad
bade
baobab
base
based
basic
bassi
basso
be
bead
beaded
bed
bedded
bedside
bee
beef
beefed
beside
biased
biassed
bib
bid
bide
bided
boa
bob
bobbed
bode
boded
bodice
boo
boob
boobed
booed
bossed
c
cab
cabbed
cabbie
caboose
cacao
cad
caddied
café
cascade
cascaded
case
cased
cassia
cease
ceased
cede
ceded
cicada
cicadae
cob
cobbed
cocci
cocoa
cod
coda
codded
code
coded
codified
coed
coffee
coif
coifed
coiffed
coo
cooed
d
dB
dab
dabbed
dad
dado
dead
deaf
deb
debase
debased
decade
decaf
decease
deceased
decide
decided
decode
decoded
deed
deeded
deface
defaced
defied
deice
deiced
deified
dice
diced
did
die
died
diocese
diode
disc
disco
discoed
disease
diseased
dissed
do
doc
dodo
doe
doff
doffed
doodad
dose
dosed
e
ease
eased
ebb
ebbed
eddied
edifice
edified
efface
effaced
f
fa
facade
face
faced
fad
fade
faded
fed
fee
feed
fiasco
fib
fibbed
fie
fief
fife
fob
fobbed
foci
foe
food
i
ice
iced
id
idea
if
sac
sad
safe
said
sassed
scab
scabbed
scad
scoff
scoffed
sea
seabed
seafood
seaside
secede
seceded
see
seed
seeded
sic
side
sided
so
sob
sobbed
sod
soda
sodded
sofa
A
Abbasid
Abe
Ac
Acadia
Ada
Addie
Aida
Asia
Assad
Assisi
B
Ba
Basie
Be
Bede
Beebe
Bessie
Bi
Bib
Bic
Bob
Bobbi
Bobbie
Boccaccio
Boise
Bose
C
Ca
Case
Casio
Cassie
Cd
Cf
Ci
Cid
Co
Cobb
D
Dacca
Dada
Debbie
Dec
Decca
Dee
Defoe
Di
Dido
Doe
E
Eco
Ed
Edda
Eddie
Effie
Essie
F
Fe
Feb
Fed
Fido
I
Iaccoca
Ibo
Ida
Io
Isaac
Issac
Combinatorics and Jason’s Deli: Index
I’m doing something that I should have done a long time ago: collecting a series of posts into one single post. The following links comprised my series on an advertisement that I saw in Jason’s Deli.
Part 1: The advertisement for the Jason’s Deli salad bar.
Part 2: Correct calculation of the number of salad bar combinations.
Part 3: Incorrect calculation of how long it would take to eat this many combinations.
Linus Pauling and the Golden Rule
Logic puzzle
From “Over 80% of people get this question wrong, can you solve it?“:
Jack is looking at Anne, Anne is looking at George. Jack is married, George is not. Is a married person looking at an unmarried person?
I’ll refer the interested reader to the above link for the answer; I’m happy to report that I got this one right.
Defining Gravity
I’m in nerd heaven: Sir Isaac Newton and Albert Einstein parodying a showstopper from Wicked.